Yuichi Nishiwaki (2013-08-31T19:45:34.000Z)
ES5 specifies "yield" as a reserved keyword, right? So there should be
no need to make it contextual.

2013/9/1 Brendan Eich <brendan at mozilla.com>:
> The empty-body basis case is one reason. A stronger reason is that yield is
> not a reserved identifier, and it is used in existing content, so function*
> allows contextual reservation without breaking backward compatibility.
>
> Another reason is to clue readers in early, when reading in source order,
> that this function is a generator, in the case where yield usage in the
> function's body is somewhat hard to see at a glance.
>
> /be
>
>> Yuichi Nishiwaki <mailto:yuichi.nishiwaki at gmail.com>
>> August 31, 2013 12:15 PM
>>
>> Hi all, I just found a post that the current generator syntax
>> (function *) seems have decided in:
>>
>> https://mail.mozilla.org/pipermail/es-discuss/2011-July/015799.html
>>
>> According to the post, the biggest reason the star syntax is adopted
>> for now is that you cannot write empty generators with star-less
>> functions in a consistent simple way. But the situation has changed,
>> and in the current spec (rev 17) yield* is now capable of taking any
>> kind of iterator, so you can make empty generators just like
>>
>> ```js
>> function * () {
>> yield * [];
>> }
>> ```
>>
>> This looks enough good and simple at least to me. And I wonder if even
>> now generators still need to be declared with 'star's. What are the
>> advantages of 'star'ed generators rather than 'star'-lesses? If not
>> exist, shouldn't it be removed (for the simplicity)?
>>
>> Thank you.
>>
>> --
>> Yuichi Nishiwaki
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>> es-discuss at mozilla.org
>> https://mail.mozilla.org/listinfo/es-discuss
>>
>
domenic at domenicdenicola.com (2013-09-08T00:52:02.971Z)
ES5 specifies `yield` as a reserved keyword, right? So there should be
no need to make it contextual.