r = /\u0020+$/g; p = r.exec("  "); q = r.exec("  "); JSON.stringify([p, q])
// "[[\"  \"],null]"

Why does calling exec the second time generate null?  When I try the
regular expression without the /g flag, I get:
// "[[\"  \"],[\"  \"]]"



-- 
"The first step in confirming there is a bug in someone else's work is
confirming there are no bugs in your own."
-- Alexander J. Vincent, June 30, 2001
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```js
r = /\u0020+$/g; p = r.exec("  "); q = r.exec("  "); JSON.stringify([p, q])
// "[[\"  \"],null]"
```

Why does calling exec the second time generate null?  When I try the
regular expression without the /g flag, I get:

```js
// "[[\"  \"],[\"  \"]]"
```