Why can't we `let s = super`?

# /#!/JoePea (7 years ago)

Why can't we store a reference to super? It seems counterintuitive and prevents possible things like

function metaStuff(sup) {
  // do something else with super or with `this`
}

class Bar extends Foo {
  constructor() {
    let s = super
    s()
    metaStuff(s)
  }
}
# Logan Smyth (7 years ago)

super() right now is a special syntactic feature, just like the new proposed import() and such. To have super behave like a variable and be consistent, super.foo() would also then be accessing a property on that variable, instead of calling a method from the parent constructor prototype. Then a whole new approach would be needed for parent class access.

# Don Griffin (7 years ago)

It seems like in the r-value usage there it could just evaluate to the method's "HomeObject" no? That would be really useful in cases where the value supplied to "extends" is complex.

Best, Don

Don Griffin Director of Engineering Sencha, Inc. www.sencha.com